Answer:
Explanation:
Explanation:
S
O
2
(
g
)
+
C
a
O
(
s
)
→
C
a
S
O
3
(
s
)
1 US ton
=
907.19
⋅
k
g
Mass of coal(kg)
=
2000
⋅
ton
×
907
⋅
k
g
⋅
ton
−
1
=
1.814
×
10
6
⋅
k
g
.
Mass of sulfur
=
1.814
×
10
6
⋅
k
g
×
2.5
%
=
45
,
350
⋅
k
g
Moles of sulfur
=
45
,
350
⋅
k
g
×
10
3
⋅
g
⋅
k
g
−
1
32.06
⋅
g
⋅
m
o
l
−
1
=
1.41
×
10
6
⋅
m
o
l
.
And thus we may have
1.41
×
10
6
⋅
m
o
l
S
O
2
produced during the daily operation.
Given the equivalence of sulfur dioxide and calcium oxide in the first equation, clearly we need
1.41
×
10
6
⋅
m
o
l
C
a
O
to produce
1.41
×
10
6
⋅
m
o
l
C
a
S
O
3
.
Mass of calcium sulfite produced daily
=
1.41
×
10
6
⋅
m
o
l
×
120.17
⋅
g
⋅
m
o
l
−
1
=
1.70
×
10
8
⋅
g
=
1.70
×
10
5
⋅
k
g
.
