The mole fraction of neon in the air is about 2.6 x 10–5. If the average molar mass of air is 28.96 g/mol what is the concentration of neon in air in ppm?

Respuesta :

Answer: The concentration of neon in air is 18.14 ppm

Explanation:

We are given:

Mole fraction of neon = [tex]2.6\times 10^{-5}[/tex]

This means that [tex]2.6\times 10^{-5}[/tex] moles of neon are present

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Molar mass of neon = 20.2 g/mol

Moles of neon = [tex]2.6\times 10^{-5}[/tex] moles

Putting values in above equation, we get:

[tex]2.6\times 10^{-5}mol=\frac{\text{Mass of neon}}{20.2g/mol}\\\\\text{Mass of neon}=(2.6\times 10^{-5}mol\times 20.2g/mol)=5.252\times 10^{-4}g[/tex]

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

[tex]\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6[/tex]

Both the masses are in grams.

We are given:

Mass of neon  = [tex]5.252\times 10^{-4}g[/tex]

Mass of solution (air) = 28.96 g

Putting values in above equation, we get:

[tex]\text{ppm of neon in air}=\frac{5.252\times 10^{-4}}{28.96}\times 10^6\\\\\text{ppm of neon in air}=18.14ppm[/tex]

Hence, the concentration of neon in air is 18.14 ppm

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