Answer:
[tex]y =4\times m-b[/tex]
[tex]Chirp = 4\times temperature-148[/tex]
Step-by-step explanation:
Let y be the number of chirp and x be the temperature.
Given:
When crickets chirp 124 times a minute = 68°F
When crickets chirp 172 times a minute = 80°F
Solution:
Standard linear equation is written as:
[tex]y =mx+b[/tex]
Where:
y = Number of chirps
m = Temperature
From the above statement, crickets chirp 124 times a minute it is about 68°F. When they chirp 172 times a minute it is about 80°F
So, the equation is written as:
[tex]124=68x+b[/tex] ----------(1)
[tex]172=80x+b[/tex] ----------(2)
Substitute equation 1 from equation 2.
[tex]172=80x+b\\124=68x+b\\-\ \ \ - \ \ \ \ \ \ -\\-------[/tex]
[tex]48 = 12x[/tex]
[tex]x = \frac{48}{12}[/tex]
x = 4
Now, substitute x = 4 in equation 1 for value of b.
[tex]124=68\times 4 +b[/tex]
[tex]b = -272+124[/tex]
b = -148
Now we substitute x = 4 and b = -148 in equation 1.
[tex]y =4\times m-b[/tex]
[tex]Chirp = 4\times temperature-148[/tex]
Therefore, the relation between cricket chirp and its temperature is given by below equation.
[tex]y =4\times m-b[/tex]
