Using quadratic function concepts, it is found that the vertex of the graph is given by (-2, -9).
What is the vertex of a quadratic equation?
A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex]
[tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]
In this problem, the equation is given by:
[tex]f(x) = x^2 + 4x - 5[/tex]
Hence the coefficients are a = 1, b = 4 and c = -5, then:
[tex]x_v = -\frac{b}{2a} = -\frac{4}{2} = -2[/tex]
[tex]y_v = -\frac{4^2 - 4(1)(-5)}{4} = -9[/tex]
More can be learned about the vertex of a quadratic function at https://brainly.com/question/24737967
