The electric potential due to ammonia at a point away along the axis of a dipole is 1.44 [tex]\times[/tex] 10^-5 V.
Explanation:
Given that 1 D = 1 debye unit = 3.34 × 10-30 C-m.
Given p = 1.47 D = 1.47 [tex]\times[/tex] 3.34 [tex]\times[/tex] 10^-30 = 4.90 [tex]\times[/tex] 10^-30.
V = 1 / (4π∈о) [tex]\times[/tex] (p cos(θ)) / (r^2)
where p is a permanent electric dipole,
∈ο is permittivity,
r is the radius from the axis of a dipole,
V is the electric potential.
V = 1 / (4 [tex]\times[/tex] 3.14 [tex]\times[/tex] 8.85 [tex]\times[/tex] 10^-12) [tex]\times[/tex] (4.90 [tex]\times[/tex] 10^-30 [tex]\times[/tex] 1) / (55.3 [tex]\times[/tex] 10^-9)^2
V = 1.44 [tex]\times[/tex] 10^-5 V.
