Answer: The molality of magnesium chloride is 1.58 m
Explanation:
To calculate the molality of solution, we use the equation:
[tex]\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}[/tex]
Where,
[tex]m_{solute}[/tex] = Given mass of solute (magnesium chloride) = 75.0
[tex]M_{solute}[/tex] = Molar mass of solute (magnesium chloride) = 95.21 g/mol
[tex]W_{solvent}[/tex] = Mass of solvent = 500.0 g
Putting values in above equation, we get:
[tex]\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m[/tex]
Hence, the molality of magnesium chloride is 1.58 m
