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A person is considered legally intoxicated with a blood alcohol level of 80 mg/dL. Assuming that blood plasma has a density of 1.025 g/mL, what is this concentration expressed in parts per million?

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Answer : The concentration expressed in parts per million is, 780.5 ppm

Explanation : Given,

Mass of alcohol = [tex]80mg/dL=80\times 10^{-5}g/mL[/tex]

Conversion used : [tex]1mg/dL=10^{-5}g/mL[/tex]

Mas of plasma = 1.025 g/mL

Parts per million (ppm) : It is defined as the mass of a solute present in one million (10⁶) parts by the mass of the solution.

Now we have to calculate the concentration in ppm.

[tex]\text{Concentration in ppm}=\frac{\text{Mass of alcohol}}{\text{Mass of plasma}}\times 10^6[/tex]

[tex]\text{Concentration in ppm}=\frac{80\times 10^{-5}g/mL}{1.025g/mL}\times 10^6=780.5ppm[/tex]

Thus, the concentration expressed in parts per million is, 780.5 ppm

The concentration expressed in parts per million is 780.5 ppm

Given:

Mass of alcohol =  80 mg/dL = [tex]80*10^{5}g/mL[/tex]

Density of plasma or Mass of plasma = 1.025 g/mL

Parts per million:

It is defined as the mass of a solute present in one million (10⁶) parts by the mass of the solution.

Calculation for units in ppm:

[tex]\text{Concentration in ppm}=\frac{\text{Mass of alcohol}}{\text{Mass of plasma}} *10^6\\\\\text{Concentration in ppm}=\frac{80*10^5g/mL}{1.025g/mL} *10^6=780.5ppm[/tex]

Thus, the concentration expressed in parts per million is 780.5 ppm.

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