Answer : The mass of nitrogen gas collected is, 290.9 grams
Explanation :
To calculate the mass of nitrogen gas we are using ideal gas equation:
[tex]PV=nRT\\\\PV=\frac{w}{M}RT[/tex]
where,
P = pressure of nitrogen gas = 1 atm
V = volume of nitrogen gas = 250 L
T = temperature of nitrogen gas = [tex]20^oC=273+20=293K[/tex]
R = gas constant = 0.0821 L.atm/mole.K
w = mass of nitrogen gas = ?
M = molar mass of nitrogen gas = 28 g/mole
Now put all the given values in the ideal gas equation, we get:
[tex](1atm)\times (250L)=\frac{w}{28g/mole}\times (0.0821L.atm/mole.K)\times (293K)[/tex]
[tex]w=290.9g[/tex]
Therefore, the mass of nitrogen gas collected is, 290.9 grams.
