Respuesta :
Answer:
sum was 300000
Step-by-step explanation:
let sum of money is placed is x rs
Term T = 3 years, rate R = 10%
Then simple interest for for 3 years is
[tex]SI= \frac{PTR}{100}\\ SI=\frac{x\times 3\times 10}{100} \\SI = 0.3x[/tex]
Sum of x will become x+0.3x = 1.3x after 3 years. now this 1.3x is kept for compound interest for two years. ie
[tex]A =P[1+R]^t\\471900=1.3x[1+\frac{10}{100} ]^2\\x=\frac{471900}{1.573} \\x=300000[/tex]
Sum was 300000
At the simple interest rate, the rate is applied only to the initial sum, while
at the compound interest, the rate is applied to the amount in the account.
- The sum of money is approximately Rs 355,847.466
Reasons:
Let P represent the sum of money invested, we have;
- [tex](P + P \cdot r \cdot t_1) \times (1 + r)^{t_2} = \mathbf{ 471900}[/tex]
Where;
P = The initial sum invested
r = The simple and compound interest rate applied = 10% = 0.1
t₁ = The number of years the money is placed at simple interest = 3 years
t₂ = The number of years the money is placed at compound interest = 2 years
Therefore;
[tex]\mathbf{(P + P \times 0.1 \times 3) \times (1 + 0.01)^{2}} = 471900[/tex]
Which gives;
[tex]P \cdot (1 + 0.3 ) \times (1 .01)^{2} = 471900[/tex]
[tex]\displaystyle P =\mathbf{\frac{471900}{(1 + 0.3 ) \times (1 .01)^{2} }} \approx 355,847.466[/tex]
The sum of money invested, P ≈ Rs 355,847.466
Learn more about simple and compound interest here:
https://brainly.com/question/24603629
https://brainly.com/question/3783619
