The quotient of the sum of 2t and 2 and twice the cube of s

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jacknjill jacknjill · Answer 1 · 2020-02-25T06:14:57+01:00

The equation according to the given verbal sentence is [tex]\frac{2 t+2}{2 s^{3}}[/tex] (after solving this [tex]\frac{t+1}{s^{3}}[/tex] ).

Step-by-step explanation:

Rewrite the given verbal sentence and so it will be easier to translate.

Given: The quotient of the sum of 2 t and 2 and twice the cube of s

sum of 2 t and 2 can be written as

2 t + 2

twice the cube of s

[tex]2 s^{3}[/tex]

Now, combine the above according to the given verbal. The quotient of the sum of 2 t and 2 and twice the cube of s means,

2 t + 2 divided by [tex]2 s^{3}[/tex]

Now, the equation would be [tex]\frac{2 t+2}{2 s^{3}}[/tex]

When solving this equation, we get

[tex]\frac{2(t+1)}{2 s^{3}}=\frac{t+1}{s^{3}}[/tex]

onyebuchinnaji onyebuchinnaji · Answer 2 · 2022-01-24T13:09:30+01:00

The quotient of the sum of 2t and 2 and twice the cube of s is [tex]\frac{t + 1}{s^3} [/tex].

The given parameters:

The sum of 2t and 2 is written as follows;

sum = 2t + 2

The cube of s is written as follows;

cube = s³

twice the cube of s = 2s³

The quotient of the sum of 2t and 2 and twice the cube of s is calculated as follows;

[tex]= \frac{2t + 2}{2s^3} \\\\ = \frac{2(t + 1)}{2s^3}\\\\ = \frac{t + 1}{s^3} [/tex]

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