Answer:
vavg = 53.7 km/h
Explanation:
In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:
[tex]vavg =\frac{xf-xo}{t-to}[/tex]
where xf - xo = total displacement = 1250 Km
If we choose tâ = 0, â t = 23h 16'= 23h + 0.27 h = 23.27 h
â [tex]vavg =\frac{1250 km}{23.27h} = 53.7 Km/h[/tex]
