A car moving at 8 m/s crashes into a barrier and stops in 0.050 s. There is a 19-kg child in the car. Assume that the child's velocity is changed by the same amount as that of the car, and in the same time period. (a) What is the impulse needed to stop the child in N*s?(b) What is the average force on the child in N? (c) What is the approximate mass of an object in kg whose weight equals the force in part (b)?

Respuesta :

Answer:

a. [tex]I=152\ N.s[/tex]

b. [tex]F=3040\ N[/tex]

c. [tex]m=309.8879\ kg[/tex]

Explanation:

Given:

  • speed of the child and the car, [tex]v=8\ m.s^{-1}[/tex]
  • time required to stop the child and the car, [tex]t=0.05\ s[/tex]
  • mass of the child, [tex]m=19\ kg[/tex]

b. Now the force experienced by the child due to change in momentum with respect to time:

[tex]F=\frac{d}{dt}(p)[/tex]

where:

[tex]p=[/tex] momentum

[tex]\frac{d}{dt} =[/tex] rate of change with respect to time

as, [tex]p=m.v[/tex] here m is constant

[tex]F=m.\frac{dv}{dt}[/tex]

[tex]F=19\times\frac{(8-0)}{0.05}[/tex]

[tex]F=3040\ N[/tex]

c.

The equivalent mass of corresponding to the force due to change in momentum:

[tex]m=\frac{F}{g}[/tex]

[tex]m=\frac{3040}{9.81}[/tex]

[tex]m=309.8879\ kg[/tex]

a.

Now the impulse:

[tex]I=F.t[/tex]

[tex]I=3040\times 0.05[/tex]

[tex]I=152\ N.s[/tex]

Answer:

(a).The impulse needed to stop the child is 152 kg m/s.

(b). The average force on the child is 3040 N.

(c). The approximate mass of an object is 310.2 kg

Explanation:

Given that,

Speed of car = 8 m/s

Mass of child = 19 kg

Time = 0.050 s

(a). We need to calculate the impulse needed to stop the child

Using formula of impulse

[tex]J=m\Delta v[/tex]

[tex]J=m\times (v_{f}-v_{i})[/tex]

[tex]J=19\times(0-8)[/tex]

[tex]J=-152\ kgm/s[/tex]

Negative sign shows the net force is in negative direction.

The impulse needed to stop the child is 152 kg m/s.

(b). We need to calculate the average force on the child

Using formula of impulse

[tex]J=Ft[/tex]

[tex]F=\dfrac{J}{t}[/tex]

Put the value into the formula

[tex]F=\dfrac{-152}{0.05}[/tex]

[tex]F=−3040\ N[/tex]

Negative sign shows the opposite direction of the force

The average force on the child is 3040 N.

(c). We need to calculate the approximate mass of an object

Using formula of force

[tex]F=mg[/tex]

[tex]m=\dfrac{F}{g}[/tex]

Put the value into the formula

[tex]m=\dfrac{3040}{9.8}[/tex]

[tex]m=310.2\ kg[/tex]

The approximate mass of an object is 310.2 kg

Hence, (a).The impulse needed to stop the child is 152 kg m/s.

(b). The average force on the child is 3040 N.

(c). The approximate mass of an object is 310.2 kg

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