Answer:
The ray's angle with respect to the face of the crystal is 71.6°
Explanation:
Given that,
Incidence angle = 27°
We need to calculate the angle of refraction
Using Snell's law
[tex]n_{oil}\sin\theta_{i}=n_{zir}\sin\theta_{r}[/tex]
[tex]\theta_{r}=\sin^{-1}(\dfrac{n_{oil}\sin\theta_{i}}{n_{zir}})[/tex]
Put the value into the formula
[tex]\theta_{r}=\sin^{-1}(\dfrac{1.518\sin27}{2.176})[/tex]
[tex]\theta_{r}=18.4^{\circ}[/tex]
We need to calculate the ray's angle with respect to the face of the crystal
Using formula of refraction
[tex]\alpha=90-\theta[/tex]
Put the value into the formula
[tex]\alpha=90-18.4[/tex]
[tex]\alpha=71.6^{\circ}[/tex]
Hence, The ray's angle with respect to the face of the crystal is 71.6°
