Answer:
4.415 g of FeSO₄
Explanation:
The balance chemical equation for given single replacement reaction is as follow;
Fe + H₂SO₄ → FeSO₄ + H₂
Data Given;
Volume = 650 mL = 0.65 L
Density at STP = 0.08988 g/L
Mass = Density × Volume = 0.08988 g/L × 0.65 L = 0.0584 g
Step 1: Calculate Moles of H₂ as;
Moles = Mass / M.Mass
Moles = 0.0584 g / 2.01 g/mol
Moles = 0.0290 mol of H₂
Step 2: Find out moles of FeSO₄ as;
According to balance chemical equation,
1 mole of H₂ is produced along with = 1 mole of FeSO₄
So,
0.0290 moles of H₂ will be produced along with = X moles of FeSO₄
Solving for X,
X = 0.0290 × 1 mol / 1 mol
X = 0.0290 moles of FeSO₄
Step 3: Calculate mass of FeSO₄ as;
Mass = Moles × M.Mass
Mass = 0.0290 mol × 151.90 g/mol
Mass = 4.415 g of FeSO₄
