Answer:
v=1.295
Explanation:
What we are given:
a=5÷(3s^(1/3)+s^(5/2)) m/s^2
Start by using equation a ds = v dv
This problem requires a numeric method of solving. Therefore, you can integrate v ds normally, but you must use a different method for a ds The problem should look like this:
[tex]\int\limits^a_b {x} \, dx[/tex]
a=2
b=1
x=5÷(3s^(1/3)+s^(5/2)) m/s^2
dx=dv
Integrate the left side the standard method.
[tex]\int\limits^a_b {x} \, dx[/tex]
a=v
b=0
dx=dv
Integrating
=v^2/2
Use Simpson's rule for the right site.
[tex]\int\limits^a_b {x} \, dx[/tex]
a=b
b=a
x=f(x)
f(x)=b-a/6*(f(a)+4f(a+b/2)+f(b)
If properly applied. you should now have the following equation:
v^2/2=5[(1/6*(0.25+4(0.162)+(0.106)]
=0.8376
Solve for v.
v=1.295
