A transport plane has a mass of 45,000 kg, a wing area of 160 m2, and an aspect ratio of 7. Assume all lift and drag due to the wing alone, with cd = 0.020 and CL,max =1.5. If the aircraft flies at 9,000 m standard altitude, make a plot of drag (in N) versus speed (from stall to 240 m/s) and determine the optimum cruise velocity (minimum drag per unit speed).

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Answer:

The answer to the question is

The optimum cruise velocity having minimum drag per unit speed is 130 m/s

Explanation:

Take the density of air from tables at 9000 m as =0.4661 kg/m³

[tex]V_{stall}=\sqrt{\frac{2W}{\rho A_{p}C_{L,max} } }=\sqrt{\frac{2(45000)(9.81N)}{0.4661(160)(1.5)} } = 89 m/s[/tex]

W = weight = mass×acceleration due to gravity (9.81 m/s²)

We then plot our drag against speed using the formula drag as follows

For each speed V, we compute

(Each V) [tex]C_{L}=\frac{2W}{\rho V^{2}A_{p} }[/tex]  ; [tex]C_{D} = C_{D}[/tex]∞ + [tex]\frac{C^{2} _{L} }{\pi AR}[/tex] ; Drag = [tex]C_{D\frac{\rho}{2}V^{2} A_{p} }[/tex]

Where AR = Aspect Ratio,  [tex]A_{p}[/tex] = Wing Area

For example when the speed = 60 m/s, [tex]C_{L}[/tex] = 3.288,  [tex]C_{D}[/tex] = 0.512, Drag = 68699.87 N The plot is attached

From the attached graph it is seen that speeds between 100 m/s and 200 m/s has the least drag therefore those speeds are more efficient. With the minimum occurring around 130 m/s

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