Respuesta :
Answer:
101.63° C
Explanation:
Volume expansivity γa = γr - γ g = 18 × 10⁻⁵ - 2.0 × 10⁻⁵ = 16 × 10⁻⁵ /K
v₂ - v₁ / v₁θ = 16 × 10⁻⁵ /K
(500 - 492 ) mL / (492 × 16 × 10⁻⁵) = θ
θ = 101.63° C
The temperature at which this occurs is 101.63 [tex]\rm \; ^\circ C[/tex] and this can be determined by using the given data.
Given :
- A glass flask has a volume of 500 mL at a temperature of 20° C.
- The flask contains 492 mL of mercury at an equilibrium temperature of 20° C.
- The temperature is raised until the mercury reaches the 500 mL reference mark.
- The coefficients of volume expansion of mercury and glass are 18 x 10–5 /K and 2.0 x 10–5 /K respectively.
First, determine the volume expansivity using the below formula.
[tex]\rm \gamma_a=\gamma_r-\gamma_g[/tex]
[tex]\rm \gamma_a=18\times 10^{-5}-2\times 10^{-5}[/tex]
[tex]\rm \gamma_a=16\times 10^{-5}/K[/tex]
So, the temperature at which this occurs can be calculated using the below formula:
[tex]\rm \dfrac{v_2-v_1}{v_1}=\theta \times \gamma_a[/tex]
Now, substitute the values of the known terms in the above formula.
[tex]\rm \dfrac{500-492}{492\times 16 \times 10^{-5}}=\theta[/tex]
Further, simplify the above expression.
[tex]\rm \theta = 101.63\;^\circ C[/tex]
For more information, refer to the link given below:
https://brainly.com/question/15267055
