raumqari
contestada

pls help me i dont know this

1) If I had 12.6 mol Cl2 how many mol of FeCl3 would be made in:
2Fe + 3Cl2 --> 2FeCl3

Question 8 options:

8.4


4.2


12.6

2) If I had 500g of Fe, how many mol FeCl3 would be produced in:
2Fe + 3Cl2 --> 2FeCl3

Question 9 options:

27.98


8.95


17.91

3)If 2 molecules of one reactant combine with 5 molecules of another to produce 3 molecules of a product, then which of the following is the correct representation of the reaction?

Question 10 options:

2A + 3B --> 5C


2A + 5B --> 3C


A2 + B5 --> C3

4) When ethane (C2H6) burns, it produces carbon dioxide and water:

2C2H6 (g) + 7O2 (g) 4CO2 (g) + 6H2O (l)

How many moles of water will be produced when 16 moles of ethane are burned?

Question 11 options:

64 moles


32 moles


48 moles

Respuesta :

Answer:

1. 12.6 moles

2. 8.95 moles

3.  2A + 5B → 3C

4. 48 moles

Explanation:

1. 2Fe + 3Cl₂ → 2FeCl₃

We assume the chlorine in excess. Ratio is 2:2

2 moles of Fe, can produce 2 moles of chloride

12.6 moles of Fe will produce 12.6 moles of chloride.

2. 2Fe + 3Cl₂ → 2FeCl₃

For the same reaction, first of all we need to convert the mass to moles:

500 g . 1mol / 55.85 g = 8.95 mol

As ratio is 2:2, the moles we have are the same, that the produced

4. The reaction for the combustion is:

2C₂H₆ (g) + 7O₂ (g) → 4CO₂ (g) + 6H₂O (l)

We assume the oxygen in excess.

Ratio is 2:6, so 2 mol of ethane produce 6 moles of water

Therefore 16 moles of ethane may produce (16 .6) / 2 = 48 moles

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE