Answer:
[tex]1.2\times 10^{-2}[/tex]
Explanation:
The given reactions are:
PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq) [tex]K_3 = 1.89\times 10^{-10}[/tex]
AgCl(aq)⇌Ag+(aq)+Cl−(aq) [tex]K_4 = 1.25\times 10^{-4}[/tex]
Required reaction is:
PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)
[tex]K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}[/tex]
