Answer:
0.01 mol of H+.
Explanation:
Equation of reaction:
Mg(s) + 2HCl(aq) --> MgCl2(aq) + H2(g)
Molar concentration = number of moles/volume
= 1*0.01
= 0.01 mol.
Dissociation:
2HCl --> 2H+ + 2Cl-
By stoichiometry,
If 2 mole of HCl dissociates to guve 2 moles of H+
Number of moles of H+ = 0.01 mol.