Answer:
130 g of O₂
Explanation:
Let's apply the Ideal Gases Law, to solve this.
Pressure . volume = moles . R . T° (K)
First of all, we need to convert the volume in mL to L, because the units of R
10000 mL . 1L/1000mL = 10L
Let's replace → 10 atm . 10L = n . 0.082L.atm/mol.K . 300K
(100 atm.L) / (0.082L.atm/mol.K . 300K) = n
4.06 moles = n
Let's convert the moles to mass → 4.06 mol . 32 g/1mol = 130 g
