Answer:
The separation on the screen between the third-order (m) is 46.36 μm
Explanation:
Given
Distance between slits is = 5.5 mm
a = 5.5 mm
Distance between slits and screen is 1.0 m
D = 1.0 m
Wavelength
y1 = 480 nm and y2 = 565 nm
imy1 = m * [tex]\frac{y1D}{a}[/tex]
imy2 = m * [tex]\frac{y2D}{a}[/tex]
when m = 3 (third-order)
Δi = i3y2 - i3y1 = 3 * [tex]\frac{(y2 - y1) D}{a}[/tex]
Δi = 46.36 μm
