The acceleration of the center of the cylinder and the tension force in the tape is mathematically given as
a=2g/3
T=ug/3
What are the forces applied on the cylinder, the acceleration of the center of the cylinder when it moves down, and the tension force in the tape?
Generally, the equation for the Liner motion is mathematically given as
Mg-T=Ma
Therefore
Mg.R=(0.5MR^2+MR^2)\alpha
[tex]\alpha=2g/3R[/tex]
b)
Where
a=\alpha R
Hence
a=2g/3
c)
For the tension T
ug-T=Ma
T=u(g-a)
T=ug/3
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