Answer:
16x^8 − 1 = (4x^4 + 1)(2x^2 + 1)(2x^2 - 1)
Step-by-step explanation:
The difference of squares:
((ax)^2n - b) = (ax^n + b)(ax^n - b)
16x^8 − 1 = (4x^4 + 1)(4x^4 - 1)
(4x^4 - 1) = (2x^2 + 1)(2x^2 - 1)
16x^8 − 1 = (4x^4 + 1)(2x^2 + 1)(2x^2 - 1)
