Answer:
0.018133
Step-by-step explanation:
Given that customers arrive randomly and independently at a service window, and the time between arrivals has an exponential distribution with a mean of 12 minutes.
Let X equal the number of arrivals per hour.
X is having average as reciprocal of 12 minutes
i.e. in one hour on an average expected customers to arrive is 60/12 =5
X being reciprocal of exponential is Poisson with parameter = 5
Probability that 10 customers arrive in one hour
=P(X=10)
=0.018133
