Answer:
16ml
Explanation:
2H2O → 2H2 + O2
2mol 2mol 1mol
volume of oxygen produced =8ml
1mole of a gas contains 22.4dm³
8ml will be equal to 8ml/22.4dm³ number of moles of oxygen gas
Using the stoichoimetric co-efficients;2moles of H2 and 1mol of Oxygen were produced
so number of moles of hydrogen will be [(2*8ml)/22.4dm³moles
but 1mol contains 22.4dm³
[(2*8ml)/22.4dm³moles will contain x
cross multiply;
x= (2*8ml)mol/22.4dm³ *22.4dm³/1mol
x=16ml
simply put ; using the stochoimetric coefficients if 2moles of H2 correspond to 1mol of O2, thus 16ml of H2 will correspod to 8ml of O2.
