Answer:
Option A) 15
Step-by-step explanation:
We are given the following in the question:
[tex]15 \sin( 100t + \dfrac{\pi}{2})[/tex]
The above expression describes a continuous signal.
We have to find the numerical value at t = 0.
Putting t = 0, we get,
[tex]\text{At t = 0}\\\\=15 \sin( 100(0) + \displaystyle\frac{\pi}{2})\\\\=15\sin\frac{\pi}{2}\\\\= 15[/tex]
Thus, the value of the signal is 15 at t = 0.
Option A) 15
