Respuesta :
Given a point (4,80) and a slope, m = 60, these can be used to formulate the equation of the graph. Using the point-slope formula:
y - y1 = m(x - x1)
y - 80 = 60(x - 4)
y - 80 = 60x - 240
y = 60x -160
Taking the x and y-intercepts:
At y = 0
0 = 60x - 160
x = 2.7
At x = 0
y = 60(0) - 160
y = -160
Therefore, you could state that there is a graph of a line that has a y intercept that is approximately negative $160 million and an x intercept that is approximately 2.7 years.
y - y1 = m(x - x1)
y - 80 = 60(x - 4)
y - 80 = 60x - 240
y = 60x -160
Taking the x and y-intercepts:
At y = 0
0 = 60x - 160
x = 2.7
At x = 0
y = 60(0) - 160
y = -160
Therefore, you could state that there is a graph of a line that has a y intercept that is approximately negative $160 million and an x intercept that is approximately 2.7 years.
Answer:
The required graph is shown below:
Step-by-step explanation:
Consider the provided information.
The company paid for these costs and made combined profits of $80 million after 4 years while profits increased $60 million per year.
Let x represents the number of years and y represents the profits.
Thus the points and slope are: (4,80) and m = 60,
The slope intercept form is: [tex]y=mx+c[/tex]
where m is the slope of the line and c is the y intercept
Substitute, x=4, y=80 and m=60 in above formula and find the y intercept.
[tex]80=(60)(4)+c[/tex]
[tex]80=240+c[/tex]
[tex]c=-240+80=-160[/tex]
Hence, y intercept is negative $160 million.
Substitute m=60 and c=-160 in slope intercept form.
The required equation is: [tex]y=60x-160[/tex]
Find x intercept by substituting y=0 in [tex]y=60x-160[/tex]
[tex]0=60x-160[/tex]
[tex]160=60x[/tex]
[tex]x\approx 2.7[/tex]
x intercept is approximately 2.7 years.
The required graph is shown below:
