An elephant, mass 1100 kg, stands on the ground above a point charge with +3 C of charge that has been buried 0.8 m beneath the ground. How much charge would you need to put on the elephant in order to make it float?

Respuesta :

Answer:

[tex]2.56071\times 10^{-7}\ C[/tex]

Explanation:

k = Coulomb constant = [tex]8.99\times 10^{9}\ Nm^2/C^2[/tex]

g = Acceleration due to gravity = 9.81 m/s²

r = Distance between charge = 0.8 m

m = Mass of elephant = 1100 kg

[tex]q_1[/tex] = Mass on first charge = 3 C

The electrostatic force will balance the weight of the elephant as the energy in the system is conserved

[tex]\dfrac{kq_1q_2}{r^2}=mg\\\Rightarrow q_2=\dfrac{mgr^2}{kq_1}\\\Rightarrow q_2=\dfrac{1100\times 9.81\times 0.8^2}{8.99\times 10^9\times 3}\\\Rightarrow q_2=2.56071\times 10^{-7}\ C[/tex]

The charge on the other particle is [tex]2.56071\times 10^{-7}\ C[/tex]

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