An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.. a) x/ tan q. b) x/sin q. cx tan q. d) x cos q.

This can be solved using trigonometric functions. The distance x serves as one leg of a triangle, and makes an angle q with the hypotenuse. The distance from the tip of the rocket to the ground make up the other leg of the triangle. So solving this:

tan q = y / x

Where: y = distance from the tip of the rocket to the ground

Therefore, y = x tan q

Among the choices, the correct answer is C.

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vintechnology vintechnology · Answer 2 · 2022-05-18T10:57:16+02:00

The distance of the tips of the rocket from the ground at that instant is x tan q°

What is a right angle triangle?

A right angle triangle has one of its angles as 90 degrees. The sides of a right angle triangle can be found using trigonometric ratios.

Therefore, the distance of the observer from the base of the launch pad is the adjacent side of the triangle formed.

Therefore, the distance of the tips of the rocket from the ground is the opposite side of the triangle.

Hence,

tan q° = opposite / adjacent

tan q° = h / x

Therefore,

h = x tan q°

learn more on right triangle here: https://brainly.com/question/1368252

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