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To determine the element that has an electron configuration of [Xe] 6s2 4f14 5d10 6p2, we must know the atomic number of Xe. From the periodic table, Xe has an atomic number of 54. We add the proceeding electrons, which is now a total of 82. The element with this atomic number is lead, Pb.

The electron configuration [Xe] 6s2 4f14 5d10 6p2 gives the configuration of element lead . option C is correct.

What is electronic configuration?

The electronic configuration is the system in chemistry based on which the filling of electrons takes place in the orbitals of s, p,d, and f orbitals according to their atomic numbers.

For example, if the element is in the 4th number of the periodic table then its electronic configuration will be 1s2 2s2 that is 4 electrons are filled in the space of the s orbital.

Like this there is a fixed common electronic configuration for all the elements present in the periodic table this specifies many things about the stability and reactivity of the elements 6s and 6p are the electrons present in the valance shell .

Therefore, the given electronic configuration is of element lead. option C is correct.

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Your question is incomplete but most probably your full question was,

Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?

A. gold (atomic number 79)

B. mercury (atomic number 80)

C. lead (atomic number 82)

D. potassium (atomic number 19)

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