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In a laboratory experiment, an ultrasound detector located at D is used to measure the distances of two moving objects, P and Q. At a certain moment, P and Q are located as shown in the diagram. What is distance PQ?. a) 6.82. b)5.66. c)4.74. d)4.24. e)3.89. .

Respuesta :

Triangle PDQ has: 

     Side "p" is opposite Angle P 

     Side "d" is opposite Angle D = 45º + 23º = 68º 

     Side "q" is opposite Angle Q 


Use the Law of Cosines: 

         d²  =  p²  +  q²   −   2 • p • q • cos(D) 

         d²  =  (4.24)²  +  (4.24)²   −   2 • (4.24) • (4.24) • cos(68º) 

         d²  =  2(4.24)²   −   2(4.24)² • cos(68º) 

         d²  =  2(4.24)² • [ 1 – cos(68º) ] 

         d  =  4.74 ft
jayilych4real

The distance PQ is 4.74 feet.

Calculations and Parameters:

Triangle PDQ has:

  •     Side "p" is opposite Angle P
  •     Side "d" is opposite Angle D = 45º + 23º = 68º
  •     Side "q" is opposite Angle Q

If we use the Law of Cosines:

d²  =  p²  +  q²   −   2 • p • q • cos(D)

d²  =  2(4.24)² • [ 1 – cos(68º) ]

d  =  4.74 ft

Read more about distances here:

https://brainly.com/question/17273444

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