Answer:
Explanation:
Given
mass of pebble [tex]m=12\ gm[/tex]
Spring constant [tex]k=200\ N/m[/tex]
extension in the sling shot is [tex]x=0.450 m[/tex]
As energy is conserved therefore Slingshot Elastic Potential Energy is converted into kinetic Energy of Pebble
[tex]\frac{1}{2}kx^2=\frac{1}{2}mv^2[/tex]
[tex]200\times (0.45)^2=12\times 10^{-3}\times v^2[/tex]
[tex]v^2=200\times (0.45)^2\times 10^{3}[/tex]
[tex]v=\sqrt{4.05\times 10^4}[/tex]
[tex]v=201.24\ m/s[/tex]
Answer:
v = 58.1 m/s
Explanation:
Mass of pebble m = 12.0 g = 0.012 kg
Spring constant of sling shot k = 200.0 N/m
Stretch in the spring x = 0.450 m
1/2 kx² = 1/2mv²
v = √kx²/m
v = √(200.0)(0.450)²/0.012
v = 58.09475019 m/s
v = 58.1 m/s
