Answer:
The concentration of benzene in this contaminated lake would be 653549ng/L.
Explanation:
The concentration C of a contaminant over a body of water of volume V can be obtained as:
C=Mass contaminant / V
In this case, the volume of the body of water:
[tex]V=200ft\cdot150ft\cdot6ft=5097.033m^3[/tex]
The mass of the contaminant (Benzene):
[tex]m=\delta V_{ben}=0.88\frac{g}{ml} 1gal(us)=3.3311kg[/tex]
Therefore:
[tex]C=\frac{m_{ben}}{V_{lake}}=6.53549\cdot10^{-4}kg/m^3=653549ng/l[/tex]
