Answer:
0.2274 mole
Explanation:
Calculation of the moles of [tex]AgBr[/tex] as:-
Mass = 42.7 g
Molar mass of [tex]AgBr[/tex] = 187.77 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{42.7\ g}{187.77\ g/mol}[/tex]
[tex]Moles= 0.2274\ mol[/tex]
According to the reaction shown below:-
[tex]Na_2S_2O_3 + AgBr\rightarrow NaBr + Na_3[Ag(S_2O_3)_2][/tex]
1 mole of [tex]AgBr[/tex] reacts with 1 mole of [tex]Na_2S_2O_3[/tex]
So,
0.2274 mole of [tex]AgBr[/tex] reacts with 0.2274 mole of [tex]Na_2S_2O_3[/tex]
Moles of [tex]Na_2S_2O_3[/tex] needed = 0.2274 mole
