Answer:
See the explanation and figure attached.
Step-by-step explanation:
For this case the first step is order the data on increasing order and we got:
0,3,4,5,6,7,9,12,12,15,18,18,19,22,24,24,,25,30,33,36
For this case we assume that the lower class limit is -0.5 and each class present a width of 10 so we have this:
Interval Frequency Relative Frequency
[-0.5-9.5) 7 7/20=0.35 (35%)
[9.5-19.5) 6 6/20=0.30 (20%)
[19.5,29.5) 4 4/20=0.2 (20%)
[29.5-39.5] 3 3/20 =0.15 (15%)
Total 20 100%
The relative frequency is calculated as [tex] Rf= \frac{f_i}{n}[/tex], where [tex] f_i[/tex] represent the frequency for the interval and n =20 the total of values given.
And then the histogram is on the figure attached.
As we can most of the values are on the left part so then we can conclude that the distribution on this case is skewed to the right. (Mode<Median<Mean)
