Answer:
f(t) = 4 - 3t + 2t^2
Step-by-step explanation:
Given:
f(t) = a + bt + ct^2
Differentiate w.r.t. "t"
f'(t) = b + 2ct
1) f(1) = 3
a + b +c = 3...........1)
2) f(2) = 6
a + 2b + 4c = 6.........2)
3) f'(1) = 1
b + 2c = 1 ...............3)
Solving above three simultaneous equations:
a = 4
b = -3
c = 2
Therefore equation becomes:
f(t) = 4 + (-3)t + (2)t^2
