Respuesta :
Answer:
After 8 hours both garage cost would be same.
Hence After 8 hours both parking garage would cost $10.
Step-by-step explanation:
Let the number of hours be 'x'.
Given;
For Garage Boyd:
flat fee for each car = $6
hourly charge = $0.50
The total cost for each car after 'x' hours is the sum of flat fee for each car and hourly charge multiplied with number of hours.
So the equation can be framed as;
Total cost = [tex]6+0.50x[/tex] equation 1
For Garage Lott:
flat fee for each car = $2
hourly charge = $1
The total cost for each car after 'x' hours is the sum of flat fee for each car and hourly charge multiplied with number of hours.
So the equation can be framed as;
Total cost =[tex]2+1x=2+x[/tex] equation 2
Now according to question,
We need to find the hours at which both cost will be the same.
We need to make both equation and equation 2 equal to find the value of 'x'.
[tex]6+0.5x=2+x[/tex]
Combining the like terms we get;
[tex]x-0.5x=6-2\\\\0.5x =4[/tex]
Dividing both side by 0.5 we get;
[tex]\frac{0.5x}{0.5} =\frac{4}{0.5}\\ \\x =8\ hrs[/tex]
Hence after 8 hours both garage cost would be same.
Now to find the cost which will be same we will substitute value of 'x' in both equation.
Garage Boyd = [tex]6+0.5x=6+0.5\times8 =6+4 = \$10[/tex]
Garage Lott: = [tex]2+x =2+8=\$10[/tex]
Hence After 8 hours both garage would cost $10.
