Answer:
[tex]$ \frac{\textbf{BC}}{\textbf{FC}}} = \frac{ \textbf{7 }}{\textbf{4}} $[/tex]
Step-by-step explanation:
Given that EF ║ AB.
So, we have: [tex]$ \frac{ \textbf{CE}} {\textbf{EA}} = \frac{ \textbf{CF}} {\textbf{FB}} $[/tex]
Also, [tex]$ \frac{ \textbf{AC}} {\textbf{CE}} = \frac{\textbf{CB}}{\textbf{CF}} $[/tex]
Note that: AC = CE + EA = 3 + 4 = 7 and CE = 3
Therefore, [tex]$ \frac{CB}{CF} = \frac{7}{4} $[/tex]
Hence, the answer.
