contestada

at an animal shelter the number of dog adoptions one weekend was 10 less than 3 times the number of cat adoptions. The number of cat adoptions plus twice the number of dog adoptions was 8

Respuesta :

ameJ
Let d= number of dog adoptions, and c= number of cat adoptions.

Create equations:

d=3c-10
c+2d=8

Solve the equations simultaneously:

c+2(3c-10)=8
c+6c-20=8
7c=28
c=4

d=3(4)-10
d=12-10
d=2

Therefore there were 4 cat adoptions and 2 dog adoptions.

Please give brainliest.

The number of dogs got adopted is 2 and Number of cat adopted is 4.

To calculate the number of cats and dogs

The number of dog in the shelter is 10 less then 3 times of cat adoption can be written as

d=3c-10 this represented for dogs.---------Equation 1

c+2d=8 this is to represented for cats.---------Equation 2

Substituting Equation 1 in Equation 2

c+2(3c-10)=8

c+6c-20=8

7c-20=8

7c=28

c=28/7

c=4

Number of cats adopted is 4

Substituting value of c in Equation 1

d=(3*4)-10

d=12-10

d=2

Number of dogs adopted is 2

The number of dogs got adopted is 2 and Number of cat adopted is 4.

To learn more about how to calculate the number of cat and dog refer:https://brainly.com/question/14462403

#SPJ2

Step-by-step explanation:

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas