Answer:
1.058 L
Explanation:
Data given:
Molarity of HNO₃ solution = 0.150 mol/L
Mass of HNO₃ = 10 g
volume of HNO₃ solution = ?
Solution:
First we have to know the number of moles for 10 g of HNO₃
Now calculate mass to moles
Formula used
no. of moles = Mass of HNO₃ / Molar mass . . . . . . . . . . (1)
molar mass of HNO₃ = 1 + 14 + 3(16)
molar mass of NaNO₃ = 63 g/mol
Put value in equation 1
no. of moles = 10 g / 63 g/mol
no. of moles = 0.1587 mol
Now to find volume
Formula used for Molarity
Molarity = number of moles of solute / volume of solution
Rearrange above equation
volume of solution = number of moles of solute / Molarity . . . . . . . (2)
Put values in equation 2
volume of solution = 0.1587 mol / 0.150 mol/L
volume of solution = 1.058 L
volume of dilute HNO₃ solution = 1.058 L
