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The equation Y-5=6(x+1) is written in point-slope form. What is the equation written in slope-intercept form?
y = kx + 11
y = 3x - 1
y = x - 4
y = 5x + 6

Respuesta :

ColeS1212
The first choice, y=kx*11, should be the answer.

Slope intercept form can be shown as y=Mx+b. Do tho this first you want to distribute on the left side of the equation so that you get y-5=6x+6. Next you want to add by 5 on both sides to isolate y which will give you y=6x+11

Answer:

[tex]y = k x +11[/tex]

Step-by-step explanation:

Point-slope form:-

step1:-

The standard of point - slope form is [tex]y-y_{1} = m (x-x_{1}[/tex]

Give equation is Y-5=6(x+1)

simplification is [tex]y=5+6 x+6[/tex]

[tex]y = 6 x+11[/tex]

This is the form of slope-intercept form

[tex]y=m x+c[/tex]

here m is the slope of the line

and y - intercept is c

so m=6 and y- intercept is 11

Step 2:-

Given option [tex]y = k x +11[/tex]

here the y- intercept is 11

so final answer is [tex]y = k x +11[/tex]

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