Answer:
80m, assuming g=10m/s^2
Explanation:
40m/s will be reduced to 0m/s in 4 seconds. 4 seconds x 40m/s would be 160m up, but you will only get half of that because you decelerate linearly to 0m/s. This leaves you with 4 x 20 = 80m.
Answer:
80m
Explanation:
According to the equation of motion, v²= u²+2as
Where v is the final velocity of the body at maximum height= 0m/s
u is the initial velocity of the body = 40m/s
a = -g (negative acceleration due to gravity since the object is thrown upward) = -10m/s²
S = H = the height of the ball above the ground
Substituting the values into the equation given, we will have;
0² = 40²-2(10)H
0 = 1600-20H
-1600 = -20H
H = -1600/-20
H = 80m
The height of the ball above the ground where it stops will be 80m
