Answer:
A. 0.8729
Step-by-step explanation:
Since the sample size is large enough (np > 10 and nq > 10), we can estimate this with a normal distribution.
μ = p
μ = 0.81
σ = √(pq / n)
σ = √(0.81 (1 − 0.81) / 2000)
σ = 0.0088
x = 1600 / 2000
x = 0.8
Find the z score:
z = (x − μ) / σ
z = (0.8 − 0.81) / 0.0088
z = -1.14
Use a calculator or table to find the probability.
P(Z > -1.14)
1 − P(Z < -1.14)
1 − 0.1271
0.8729
