Answer:
Height[tex]=22\ feet[/tex]
Step-by-step explanation:
Let Kite is at point [tex]Q[/tex] and My place is [tex]P[/tex].
[tex]PQ=length\ of\ string=28\ feet[/tex]
Let [tex]RQ[/tex] be height and it is[tex]=h\ feet[/tex]
[tex]\angle QPR=52\textdegree[/tex]
[tex]Now\ in\ \triangle PQR\\\\\sin \angle QPR=\frac{Opposite}{Hypotenuse}=\frac{QR}{PQ}\\\\\sin 52=\frac{h}{28}\\\\h=28\times \sin 52\\\\h=28\times 0.7880\\\\h=22.064\approx 22\ feet[/tex]
