Answer
given,
radius of earth,r = 1.5 x 10¹¹ m
Time,T = 365 days
= 365 x 24 x 3600 s
earth velocity,
[tex]v=\dfrac{2\pi r}{T}[/tex]
[tex]v=\dfrac{2\pi (1.5\times 10^{11})}{365\times 24\times 3600}[/tex]
v = 3 x 10⁴ m/s
centripetal acceleration of the earth
[tex]a = \dfrac{v^2}{r}[/tex]
[tex]a = \dfrac{(3\times 10^4)^2}{1.5\times 10^{11}}[/tex]
a = 6 x 10⁻³ m/s²
