Answer:
The range of [H⁺] is from 2.51 x 10⁻⁶ M to 6.31 x 10⁻⁶ M,
Explanation:
To answer this problem we need to keep in mind the definition of pH:
So now we calculate [H⁺] using a pH value of 5.2 and of 5.6:
-5.2 = log [H⁺]
[tex]10^{-5.2}[/tex] = [H⁺]
6.31 x 10⁻⁶ M = [H⁺]
-5.6 = log [H⁺]
[tex]10^{-5.6}[/tex] = [H⁺]
2.51 x 10⁻⁶ M = [H⁺]
Learn more about:
https://brainly.com/question/13054663