Respuesta :
Answer:
Wavelength, [tex]\lambda=6.52\times 10^{-4}\ m[/tex]
Explanation:
Given that,
Speed of the sound in the rat tissues, v = 1500 m/s
Let [tex]\lambda[/tex] is the wavelength of an ultrasonic wave. The speed of a wave is given by the relation as follows:
Let us assume that the frequency of ultrasonic wave is 2.3 MHz.
[tex]v=f\lambda[/tex]
[tex]\lambda=\dfrac{v}{f}[/tex]
[tex]\lambda=\dfrac{1500\ m/s}{2.3\times 10^{6}}[/tex]
[tex]\lambda=6.52\times 10^{-4}\ m[/tex]
So, the wavelength of an ultrasonic wave is [tex]6.52\times 10^{-4}\ m[/tex]. Hence, this is the required solution.
Answer:
The wavelength of the ultrasound wave used in the study was closest to [tex]6.52 \times 10^{-4} m$[/tex] .
Explanation:
Given:
Speed of sound in the rat tissues [tex]=1500 m/s[/tex]
Step 1:
Let [tex]v[/tex] be the speed of the sound in the rat tissues,
[tex]v = 1500 m/s[/tex]
[tex]\lambda[/tex] is the wavelength of an ultrasonic wave
The frequency of an ultrasonic wave is [tex]2.3 MHz.[/tex]
The equation to find The speed of a wave is,
[tex]$v=f \lambda$[/tex]
From this,
[tex]$\lambda=\frac{v}{f}$[/tex]
Substitute the values,
[tex]$\lambda=\frac{1500 \mathrm{~m} / \mathrm{s}}{2.3 \times 10^{6}}$[/tex]
[tex]$\lambda=6.52 \times 10^{-4} \mathrm{~m}$[/tex]
Therefore, The wavelength of the ultrasound wave used in the study was closest to [tex]6.52 \times 10^{-4} m$[/tex] .
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