A 45kg ice skater stands at rest on the ice. A friend tosses the skater a 5kg ball. The skater and the ball then move backwards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?

Respuesta :

The initial speed of the ball is 5 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum: in absence of external forces, the total momentum of the skater + ball system must be conserved. So we can write:

[tex]p_i = p_f[/tex]

[tex]mu=(m+M)V[/tex]

where:

m = 5 kg is the mass of the ball

u  is the initial velocity of the ball

M = 45 kg is the mass of the ice skater

V = 0.5 m/s is the final velocity of the skater+ball together

Solving for u, we can find the initial velocity of the ball:

[tex]u=\frac{m+M}{m}V=\frac{5+45}{5}(0.5)=5 m/s[/tex]

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