The image height is -10 cm (the image is upside down)
Explanation:
We can solve the problem by using the mirror equation:
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where:
f = 5 cm is the focal length of the mirror
p = 10 cm is the distance of the object from the mirror
q is the distance of the image from the mirror
Solving for q, we find:
[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{5}-\frac{1}{10}=\frac{1}{10}\\\rightarrow q= 10 cm[/tex]
So, the distance of the image from the mirror is 10 cm.
Now we can find the image height by using the magnification equation:
[tex]\frac{y'}{y}=-\frac{q}{p}[/tex]
where
y' is the height of the image
y = 1 cm is the height of the object
and using
p = 10 cm
q = 10 cm
We find the size of the image:
[tex]y' = -\frac{qy}{p}=-\frac{(10)(1)}{10}=-10 cm[/tex]
where the negative sign indicates that the image is upside down.
#LearnwithBrainly
